Formula Parser does not support ! as unary in Boolean types
Description
Playing with the if statement:
MODIFY:Face|SET|if(IsLong==False,15,5,25,25)|PRIORITY=100
MODIFY:Reach|SET|if(IsLong=False,10,5)|PRIORITY=100
IsLong is a BOOLEAN
I tried != without any success as well.
Environment
None
Activity
Show:
Tom Parker
March 4, 2016, 11:31 PM
This requires some deep work in the parser itself to allow for ! as a unary operator
Tom Parker
March 5, 2016, 12:22 AM
PR#1020
Fixed
Assignee
Tom Parker
Reporter
Andrew Maitland
Labels
None
Theme
None
Epic/Theme
None
Pending User Input
No
Fix versions
Priority
Configure