Formula Parser does not support ! as unary in Boolean types

Description

Playing with the if statement:

MODIFY:Face|SET|if(IsLong==False,15,5,25,25)|PRIORITY=100

MODIFY:Reach|SET|if(IsLong=False,10,5)|PRIORITY=100

IsLong is a BOOLEAN

I tried != without any success as well.

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Tom Parker
March 4, 2016, 11:31 PM

This requires some deep work in the parser itself to allow for ! as a unary operator

Tom Parker
March 5, 2016, 12:22 AM

PR#1020

Fixed

Assignee

Tom Parker

Reporter

Andrew Maitland

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